Question

The value of ( n+1=6 ) then, ( n+1=6 )
( 6+0=6 )
( 5+1=6 ) and ( 4+2=6 )
All above can be possible as values of 'n' are greater than the values of " But, ( 3+3=6 )
( 2+4=6 )
( 1+5=6 )
( 0+6=6 )
( 3+3 ) not possible as value of ( 1=(n-1) ), and other values cannot be possible as value of 'n' are less than I. Hence total number of sub-shells would be 3 .

# 25. If n + 1 = 6, then total possible number of subshells would be (1) 3 (2) 4 (4) 5 (3) 2

Solution