Question # Three capacitors ( 3 mu F, 6 mu F ) and ( 6 mu F ) are connected in series to a source of ( 120 mathrm{V} ). The potential difference, in volt, across the ( 3 mu mathrm{F} ) capacitor will be

# Three capacitors ( 3 mu F, 6 mu F ) and ( 6 mu F ) are connected in series to a source of ( 120 mathrm{V} ). The potential difference, in volt, across the ( 3 mu mathrm{F} ) capacitor will be

(a) ( 24 mathrm{V} )

(b) ( 30 mathrm{V} )

(c). ( 40 mathrm{V} )

(d) ( 60 mathrm{V} )

Solution

( 3 mu F, 6 mu f, 6 mu f ) series [ frac{1}{c_{e q}}=frac{1}{3}+frac{1}{6}+frac{1}{6}=frac{2}{3} ] ( C_{q}=frac{3}{2}: ) [ q=C_{e q} V=frac{3}{2} times 120=180 mu C ] Vacross 3 Mμcapaitor ( =frac{q}{3} ) [ =frac{180}{3}=60 mathrm{V} ] Option d is correct answer.