Question

(26) ( operatorname{mgcl}_{2} cdot x+operatorname{tg} theta rightarrow Delta operatorname{mg}left(1 / 2+begin{array}{c}sqrt{1}_{2} 0 10.89end{array}right) )
( 20 cdot 39 )
( Rightarrow 53 cdot 20=frac{18 x}{95+18 x} times 100 )
( Rightarrow 53 cdot 20(95+18 x)=18000 )
( Rightarrow 5054+957.6 mathrm{n}=1800 mathrm{m} )
( 7800 x-957.6 n=5054 )
( Rightarrow 842.4 n=5054 )
( Rightarrow n=frac{5054}{842.4}=5.99 mathrm{m}(mathrm{G}) mathrm{Nm} )
Aus oppion( (4)

# 26. 20.3 g sample of pure MgCl,H,O on heating form 10.8 g water and anhydrous MgCl. The value of x is (Molecular mass of MgCl2 = 95) (1) 2 (2) 4 (3) 5 (4) 6

Solution