Question

Molar ratio of He and ( C H_{4} ) is 4: 1
Partial pressure ratio of He and ( C H_{4} )
is 16: 4
( frac{n_{H e}}{n_{C H_{4}}}=sqrt{frac{M_{C H_{4}}}{M_{H e}}} times frac{P_{H e}}{P_{C H_{4}}} )
since total pressure ( =20 ) bar
( =sqrt{frac{16}{4}} times frac{16}{4} )
since time of diffusion for both is same
( =8: 1 )
The composition of mixture initially
gone out for He and ( C H_{4} ) is 8: 1

# 26. A 4:1 mixture of helium and methane is contained in a vessel at 10 bar pressure. Due to a hole in the vessel, the gas mixture leaks out. The composition of the mixture effusing out initially is (a) 8:1 (b) 8:3 (c) 4:1 (d) 1:1

Solution