Question

26. A 4:1 mixture of helium and methane is contained in a vessel at 10 bar pressure. Due to a hole in the vessel, the gas mixture leaks out. The composition of the mixture effusing out initially is (a) 8:1 (b) 8:3 (c) 4:1 (d) 1:1

JEE/Engineering Exams

Chemistry

Solution

130

4.0 (1 ratings)

Molar ratio of He and ( C H_{4} ) is 4: 1 Partial pressure ratio of He and ( C H_{4} ) is 16: 4 ( frac{n_{H e}}{n_{C H_{4}}}=sqrt{frac{M_{C H_{4}}}{M_{H e}}} times frac{P_{H e}}{P_{C H_{4}}} ) since total pressure ( =20 ) bar ( =sqrt{frac{16}{4}} times frac{16}{4} ) since time of diffusion for both is same ( =8: 1 ) The composition of mixture initially gone out for He and ( C H_{4} ) is 8: 1