Question

26. (S) The thermal decomposition of A + B + C has rate constant x molelit' min at a given temperature. How would dA will change if concentration of A is doubled keeping temperature constant (a) will increase by 2.828 times (b) will increase by 4 times (c) will increase by 11.313 times (d) will not change

JEE/Engineering Exams

Chemistry

Solution

114

4.0 (1 ratings)

( A longrightarrow ) sate constants is x mole" 2 lin [ (r) ] ( r ) ( left(frac{operatorname{ros} 1 e}{sqrt{0} 1}right)^{1-x} T^{-1} ) Thus ( x=-k quad[A]^{3 / 2} ) on doubling the concentranion 0,7 ( gamma_{1}=k[2 A]^{3 / 2} ) ( 8,=2 cdot 828 mathrm{kPA}]^{3 / 2} ) [ r_{1}=-2 cdot 8280 ] ( -frac{d A}{d t}=gamma quad ) which is increased ( b y ) ( 2 cdot 828+i m<8 )