Question

( begin{aligned} f_{2} times frac{1}{2} &=10 f_{2} &=20 mathrm{kg} omega+1 end{aligned} )
( mathcal{L} )
( F_{2} cos 30^{circ}=F_{1} )
( begin{aligned} therefore F_{1} &=20 times frac{sqrt{3}}{2} f_{1} &=10 sqrt{3} end{aligned} )
Smaller berece ( 10 sqrt{3} mathrm{Kg} omega mathrm{d} )

# 26. The resultant of two forces acting at an angle of 150° is 10 kgwt, and is perpendicular to one of the forces. The magnitude of smaller force is (1) 10/3 kgwt (3) 20 kgwt (2) 20/3 kgwt (4) 10 kgwt

Solution