Question

27. (3) Given ( x+frac{1}{x}=2 )
( Rightarrow quad x^{2}+1=2 x )
( Rightarrow quad x^{2}+1-2 x=0 )
( Rightarrow quad frac{x-1}{x^{3}}=frac{x^{3}+frac{1}{x^{3}}}{x^{18}+frac{1}{x^{18}}}=frac{1+frac{1}{1}}{1+frac{1}{1}}=frac{2}{2}=1 )

# 27. if (x + 1) = 2, then find the value 27. if x + - RRB NTPC (Phase I) 2016 (3) 1 ON (2) 5

Solution