Question

( u x=u cos theta )
( u y=u sin theta )
when argle ( =phi )
( V x=v cos phi quad ) that must be equal to ( u_{x}=u cos theta )
( mathrm{so}, quad mathrm{v} cos phi=mathrm{ucos}(mathrm{O}) )
( V=frac{u cos theta}{cos theta}=operatorname{ucos} theta cdot sec phi )
OPtion CC ) is correep

# 27 particle is thrown with a speed u at an angle with the horizontal. When the particle makes an angled with the horizontal, its speed changes to v, then (B) v=u cos O. cos o (A) v=u cos e (D) v=u sec O. cos o (C) v = u cos 0 sec o 450 with horizontal The equation for the

Solution