Question

28. (4) 16 men ( =20 ) women ( Rightarrow quad 4 mathrm{men}=5 ) women
( therefore 28 mathrm{men} ) and 15 women ( =28 times frac{5}{4}+15 )
( =50 ) women
By ( M_{1} D_{1}=M_{2} D_{2} )
( 20 times 25=50 times D_{2} )
( therefore quad D_{2}=frac{20 times 25}{50}=10 ) days

# 28. If 16 men or 20 women can do a piece of work in 25 days. In what time will 28 men and 15 women do it? (1) 142 days (3) 182 days (2) 33. days (4) 10 days days

Solution