3.-1.1/3 are the zeroes of the cubic polynomial ARN

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( 3,-1,1 / 3 ) are the zeroes ( -x-(x-3)(x+1)(x-1 / 3)=0 ) ( t ) ( left(x^{2}-2 x-3right)(x-1 / 3)=0 ) ( left.x^{2} mid begin{array}{cc}x^{3}-2 x^{2}-3 x & =0 frac{-1}{3} x^{2}+frac{2}{3} x+1end{array}right) quad=0 ) z) ( x^{3}-frac{7}{3} x^{2}-frac{7}{3} x+1=0 )

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