Question

( A t t=1, quad ) Sppenation ( =Q-1 / 2=1.5 )
( t=2 )
( t=3 quad "=4-2=2 )
( t=4 quad " quad 5-2.5=2.5 )
( therefore quad A t quad t=3 . )

# 3. (3) 04 M/S Two particles A and B start from the same point and move in the positive x-direction. In a time interval of 2.00 s after they start, their velocities v vary with time t as shown in the following figures. What is the maximum separation between the particles during this interval? v (m/s) Particle A 2.00 1.00- 1.00 2.00 → t(s) v (m/s) Particle B 2.00 --- 1.00 --- 1.00 2.00t(s)

Solution