Question

( frac{4}{x+1} leq 3 operatorname{and} 3 leq frac{6}{x+1} )
( 4 leq 3 x+3 ) and ( 3 x+3 leq 6 )
( frac{1}{3} leq x ) and ( x leq 1 )
( frac{1}{2}, 1 )
opton ( A )

# 3. $35 (x>0), then the solution set is (d) None

Solution

Instasolv

Solution