3. $35 (x>0), then the solution set is (d) None

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( frac{4}{x+1} leq 3 operatorname{and} 3 leq frac{6}{x+1} ) ( 4 leq 3 x+3 ) and ( 3 x+3 leq 6 ) ( frac{1}{3} leq x ) and ( x leq 1 ) ( frac{1}{2}, 1 ) opton ( A )

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