Question

( frac{3}{x}+frac{4}{y}=1 )
.. ( quad frac{4}{x}+frac{2}{y}=frac{11}{12} )
Multiplying
(ii) by ( 2 Rightarrow frac{8}{x}+frac{4}{y}=frac{22}{12} )
Subtracting (i) and (iii) ( Rightarrow frac{5}{x}=frac{10}{12} therefore x=frac{5 times 12}{10}=6 )
Substituting ( x=6 text { in ( } i) ) ( Rightarrow frac{3}{6}+frac{4}{y}=1 Rightarrow frac{4}{y}=1-frac{1}{2}=frac{1}{2} quad therefore quad y=8 )
Hence, ( x=6 ) and ( y=8 )

# 3 4 4 2 Solve for x and y:-+-=1; -+-=- x x y 11 12

Solution