Question

The energy required to melt ( 100 mathrm{J} ) of ice is
[
begin{aligned}
8 &=m L=log _{x} 33 J / g
&=3300 mathrm{J}
end{aligned}
]
If ( n ) be the number fromantar roniation then energyy
[
E=n h v
]
( therefore quad n h v=33005 )
[
begin{aligned}
Rightarrow n &=frac{3300}{h^{2}}
&=frac{3300}{6.62 times 10^{-3} 4 times 4.98 times 10^{14}}
sqrt{n} &=10^{22}
end{aligned}
]

# 3. The number of quanta of radiation of frequency 4.98 * 1014 s-1 required to melt 100 g of ice are (latent heat of melting of ice is 33 joule per g) (1) 1020 (2) 1022 (3) 1024 (4) 6.023 * 1021 9. In

Solution