Question
( 9 ; 5 )
comme ( x )
( a=9 )
( b )
( a+c )
+20
( left|begin{array}{ccc}x+1 & x+2 & x+a x+2 & x+3 & x+b x+3 & x+4 & x+cend{array}right|=mid begin{array}{ccc}x+1 & x+2 & x+9 x+2 & x+3 & x+(0+d) x+3 & x+4 & x+(0+2 d) R_{2} & x_{2}-R Lend{array} )
( R_{3} rightarrow R_{3}-R_{2} )
( left|begin{array}{ccc}x+1 & x+2 & x+9 1 & 1 & d 2 & 2 & 2 d R_{3} & rightarrow & R_{3}-2 cdot R_{2}end{array}right| )
( left|begin{array}{ccc}x+1 & x+2 & x+9 1 & 1 & d 0 & 0 & 0end{array}right|=0 )
( = )
rou
let

3. X+1 If a, b, c are in AP, then x +2 x +3 +2 +3 X+4 X+a +b equals - X+
Solution
