Question

[
x=2^{sqrt{5}} 5^{sqrt{2}}
]
on applying logarithm on botb sides
On compalision with
[
begin{array}{l}
=(sqrt{A}-sqrt{B}) log _{10} 2+sqrt{B}
A=5
B=2
end{array} Rightarrow begin{array}{l}
A+B=7
end{array}
]

# 31. If x = (215) (sv2), then log,,X = VÁ - VB) (log,2) + VB. The value of (A + B) equals (1) 7 (2)9 (4)11 (5)13 11

Solution