Question

Let the price pel ( k g ) of sugar before (original) be ( x ) New price per ( k g=x^{prime}=0.8 x )
old ( cot theta operatorname{sen} g a x=frac{36}{x} ) rg
[
text { New wrig sugar }=frac{36}{0.8 x}=frac{45}{x} mathrm{kg}
]
given that, ( (text { New wt })-(theta 4 d w)=frac{500}{1000} mathrm{kg} )
[
begin{array}{c}
frac{45}{x}-frac{36}{x}=0.5
9=0.5 x
sqrt{x=18}
end{array}
]
original price is ( overline{2} 18 ) ans:
(2) ( ₹ 18 )

# 31. The price of sugar is reduced by 20%. Now a person can buy 500 g more sugar of 36. The original price of the sugar per kg was (1) 14.40 (2) 18 (3) 15.60 (4) 16.50

Solution