Question

( 3^{2 x+3}-243 cdot 3^{x}+9=0 )
( 9left(3 times 3^{2 x}-27 times 3^{x}+1right)=0 )
( operatorname{let} 3^{x}=t )
( 3 t^{2}-27 t+1 )
( t=frac{27 pm sqrt{9729-12}}{6} )
( x=log left(frac{27 pm sqrt{717}}{6}right) )

# 324+3 - 24303 +9=0. Find a.

Solution