Question

The equation of projectile is given by, ( y=x tan theta-frac{1}{2} frac{g x^{2}}{u^{2} cos ^{2} theta} )
( tan theta=frac{u_{y}}{u_{x}}=frac{2}{1}=2 )
( therefore y=2 x-frac{1}{2} frac{10 x^{2}}{left(1^{2}+2^{2}right) times frac{1}{1+tan theta}}=2 x-frac{1}{2} frac{10 x^{2}}{left(1^{2}+2^{2}right) times frac{1}{5}} )
( Rightarrow y=2 x-5 x^{2} )

# 33. A projectile is given an initial velocity of (i +2j) m/s. where i is along the ground and j is along the vertical. If g = 10 ms?, the equation of its trajectory is: (a) y = 2x - 5x2 (b) 4y = 2x - 5x2 (c) 4y = 2x - 25x2 (d) x = y - 5x2

Solution