33. For O
Question
Fullscreen

33. For O
JEE/Engineering Exams
Maths
Solution
186
Rating
4.0 (1 ratings)
Fullscreen
( begin{aligned} & tan x+tan 2 x+tan 3 x=0 Rightarrow &left(frac{tan x+tan 2 x}{1-tan x cdot tan 2 x}right)(1-tan x cdot tan 2 x)+tan 3 x=0 end{aligned} ) ( Rightarrow tan 3 x(1-tan x cdot tan 2 x)+tan 3 x=0 quadleft(therefore tan (x+y)=frac{tan x+tan y}{1-tan x+tan y}right) ) ( Rightarrow tan 3 x[2-tan x cdot tan 2 x]=0 ) So, either tan ( 3 x=0 ) or ( 2-tan x cdot tan 2 x=0 )

Quick and Stepwise Solutions Just click and Send Download App OVER 20 LAKH QUESTIONS ANSWERED Download App for Free