Question

33. (2) ( tan left(-405^{circ}right) )
By sign of Trigonometric function
[
tan (-theta)=-tan theta=-tan left(405^{circ}right)-tan left(360^{circ}+45^{circ}right)
]
By sign of Trigonometric function
[
begin{aligned}
tan left(360^{circ}+thetaright) &=tan theta
&=-tan 45^{circ}=-1
end{aligned}
]

# 33. The value of tan(-405°) is RRB NTPC (Phase 1) 2016 (1) 1 (2) -1 (3) o (4) O

Solution