Question

Prove
[
begin{array}{r}sec 40-sec ^{2} theta=pi a n^{4} theta+tan ^{2} theta left(1+tan ^{2} thetaright) sec ^{2} theta-sec ^{2} theta left(1+tan ^{2} thetaright) sec ^{2} theta-left(1+tan ^{2} thetaright) left(1+tan ^{2} thetaright)left[sec ^{2} theta-1right] left(1+tan ^{2} thetaright) tan ^{2} theta tan ^{2} theta+tan ^{4} thetaend{array}
]

# 34. Prove that: secte-sec2 = tant e + tan- o. ICBSE 2015]

Solution