Question

37) The mass defect in a particular nuclear reaction is 0.3grams. The amount of energy liberated in kilowatt hours is : (Velocity of light = 3x10 m/s (1) 1.5 x 106 (2) 2.5 x 106 (3) 3 x 105 0 7.5 x 10°

JEE/Engineering Exams

Physics

Solution

180

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( Rightarrow K omega+h=3.6 times 10^{6} mathrm{J} ) sy userated ( =9=operatorname{Am} x c^{2}left(because c=3 x mid 0^{8} m bright) ) ( =3 times 10^{-4} timesleft(3 times 10^{8}right)^{2} ) ( =3 times 10^{-4} times 9 times 10^{16} ) ( =27 times 10^{12} mathrm{J} ) ( =27 times 10^{12} mathrm{J} times frac{1 mathrm{KWH}}{3 cdot 6 times 10^{6} mathrm{f}} ) ( =frac{27}{3.6} times 10^{12-6} ) ( =frac{27}{364} times 10 times 10^{6} ) ( =frac{3}{4} times 10 times 10^{6} ) ( =0.75 times 10 times 10^{6} ) ( 9=7.5 times 10^{6} mathrm{kw} mathrm{Hr} ) ( = ) option (4)