Question

# 38. A (3) 0,03 (4) COA be 29. The average molar mass of a mixture of CO(g) and CO,(g) is 37. The mole percentage of CO(g) in the mixture is approximately (1) 37.30 (2) 43.75 (3) 56.68 (4) 65.25 alleolution is an molal and its 30

Solution

Dearstudent ( sin )

Let wo assume the vemoiss ( x % ) of 00 in present ( tan C O_{2} cos u quad b_{2}((100-x) cdot 1 )

on

Glen

( A F C_{2} times 828+(100-x) 44=37 )

( x times 828+(100-x) 44= )

[

100

]

-2

[

28 x+4400-24 x+3700

]

10

[

Rightarrow quad-16 x=-700

]

( 16=100 )

So, mole percentage of wo will be 43.75

28

of tion - 2 Regards