Question

( left(log _{3} 6-log _{3} 2right)left(log _{3} 6+log _{3} 2right)=log _{3} 12left(log _{3}^{2} n-2right) )
( log _{3} 2=log _{3}left(12 g_{3}^{2} x-2right) )
( therefore log _{3}^{2} x=3 )
( therefore log _{3} x=sqrt{3} )
( x=3 ) onif baxis
( 12=10^{sqrt{3}} )

# 38. log 6-log; 2 = (logʻx-2)log, 12

Solution