38. log 6-log; 2 = (logʻx-2)log, 12...
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38. log 6-log; 2 = (logʻx-2)log, 12

JEE/Engineering Exams
Maths
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( left(log _{3} 6-log _{3} 2right)left(log _{3} 6+log _{3} 2right)=log _{3} 12left(log _{3}^{2} n-2right) ) ( log _{3} 2=log _{3}left(12 g_{3}^{2} x-2right) ) ( therefore log _{3}^{2} x=3 ) ( therefore log _{3} x=sqrt{3} ) ( x=3 ) onif baxis ( 12=10^{sqrt{3}} )
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