Question

( 2 div 20_{3}^{-2}+underline{1}_{2} rightarrow 3_{1} 0_{6}^{-2}+21 )
Oxidation of ( 0 cdot u_{5} s_{2} o_{3}^{-2}=+2 )
( a_{n+1} quad s_{-1} 0_{b}^{-2}=+2 cdot s )
Mere ( cos ^{-2} 3 ) has 2 mole
( 18 quad 4 ) then
oxidation numbern
[
4 times 2=8
]
In product side ( triangle 406 ) hrs Imole
element is 4 bhen ( cos ^{-1} )
sulphur the oxidation mumber is ( 4 times 2.5 )
10
Diff. If exchanged eleatoon ( =10^{circ} mathrm{Q} )
2
eq wor of ( mathrm{Na}_{2} mathrm{S}_{2} mathrm{O}_{3} ) is
( frac{operatorname{ros} theta cdot w t cdot d r N a_{2}}{r !} )
( x )
no of exchanget e
bo.
noferetor =
( e_{eta} cdot operatorname{arting} N a_{2} sin B=frac{158^{x_{2}}}{2} )
( =158 )
option (1) is correct

# 4 6 37. In the reaction, 25,0,2- + 1, 502- + 21-, the eq. wt. of Na,s,o, is equal to its : (1) Mol. wt. (2) Mol. wt./2 (3) 2 x Mol. wt. (4) Mol. wt./6 ZANODE02BOAL-BO WNURTURECHEMEN 1

Solution