Question

4 6 37. In the reaction, 25,0,2- + 1, 502- + 21-, the eq. wt. of Na,s,o, is equal to its : (1) Mol. wt. (2) Mol. wt./2 (3) 2 x Mol. wt. (4) Mol. wt./6 ZANODE02BOAL-BO WNURTURECHEMEN 1

NEET/Medical Exams

Chemistry

Solution

126

4.0 (1 ratings)

( 2 div 20_{3}^{-2}+underline{1}_{2} rightarrow 3_{1} 0_{6}^{-2}+21 ) Oxidation of ( 0 cdot u_{5} s_{2} o_{3}^{-2}=+2 ) ( a_{n+1} quad s_{-1} 0_{b}^{-2}=+2 cdot s ) Mere ( cos ^{-2} 3 ) has 2 mole ( 18 quad 4 ) then oxidation numbern [ 4 times 2=8 ] In product side ( triangle 406 ) hrs Imole element is 4 bhen ( cos ^{-1} ) sulphur the oxidation mumber is ( 4 times 2.5 ) 10 Diff. If exchanged eleatoon ( =10^{circ} mathrm{Q} ) 2 eq wor of ( mathrm{Na}_{2} mathrm{S}_{2} mathrm{O}_{3} ) is ( frac{operatorname{ros} theta cdot w t cdot d r N a_{2}}{r !} ) ( x ) no of exchanget e bo. noferetor = ( e_{eta} cdot operatorname{arting} N a_{2} sin B=frac{158^{x_{2}}}{2} ) ( =158 ) option (1) is correct