Question

4. Find out slope of tangent at the point (3, 1) of the curve x2 + 5 y2 = 14.

JEE/Engineering Exams

Maths

Solution

4.0 (1 ratings)

( x^{2}+5 y^{2}=14 ) ( 2 x+10 y frac{d y}{d x}=0 ) ( 7 ln frac{d y}{d x}=frac{-x}{5 y} ) ( operatorname{at}(3,1) ) ( frac{d y}{d x}=frac{3}{sin x}=frac{3}{5} )