Question

4. How much volume of chlorine is required to form 11.2 L of HCl at 273 K and 1 atm pressure ?

11th - 12th Class

Chemistry

Solution

550

4.0 (1 ratings)

( mathrm{H}_{2}+mathrm{c}_{2} rightarrow 2 mathrm{HCl} quad mathrm{PV}=mathrm{nRT} ) ( 1 times 11.2=mathrm{n} times 0.0821 times 273 ) ( frac{11 cdot 2}{22.41}=mathrm{n} ) ( frac{1}{2} mathrm{mol}=n ) [ begin{aligned} 1 times v &=frac{1}{2} mathrm{mol} times frac{1}{2}=frac{1}{4} mathrm{mol} 1 times v &=frac{1}{9} times 22.4 v &=frac{22.4}{4}=5.6 mathrm{L} end{aligned} ]