4. What values between 0° and 360° ...
Question

# 4. What values between 0° and 360° may A have when 11. tan A=-1 10. cos A=-= 9. sin A = to 14. cosec A=-2 13. sec A== 12. cot A=-13 77. wher Letc pend Mea Tmnoga in terms of the ratios of a positive angle, which is less the

JEE/Engineering Exams
Maths
Solution
251
4.0 (1 ratings)
( underline{90} sin A=frac{1}{sqrt{2}}=sin frac{pi}{4}=sin (180-45)=frac{3.1 mathrm{A}}{5} ) ( sin A=sin frac{n}{4}=sin left(n-frac{n}{4}right)=frac{8 operatorname{in} 3 n}{4} ) ( A=frac{pi}{4}, frac{3 pi}{4} ) An ( log cos A=frac{-1}{2}=-cos frac{pi}{3}=cos left(1-frac{n}{3}right)=cos left(n+frac{pi}{3}right) ) ( Rightarrow cos A=-frac{1}{2}=cos frac{2 n}{3}=cos frac{4 pi}{3} ) ( A=frac{2 n}{3}, frac{4 pi}{3} quad underline{c m} ) 11Q ( tan A=-1=-tan left(frac{pi}{4}right)=tan left(r-frac{-n}{4}right)=tan left(2 pi-frac{pi}{4}right) ) ( tan A=tan frac{3 pi}{4}=tan frac{7 pi}{4} ) ( A=frac{3 n}{4}, frac{7 pi}{4} ) ( frac{120}{=} cot A=-sqrt{3}=-cot frac{pi}{3}=cot left(1-frac{pi}{3}right)=cot left(2 pi-frac{pi}{3}right) ) ( cot A=cot frac{2 pi}{3}=cot frac{5 pi}{3} cdot 8 A=frac{2 pi}{3}, frac{5 pi}{3} ) 139 ( sec A=frac{-2}{sqrt{3}}=-sec frac{pi}{6}=sec left(pi-frac{pi}{6}right)=sec left(frac{1+pi}{6}right) ) ( sec A=sec frac{5 pi}{6}=sec frac{pi pi}{6} quad Rightarrow A=frac{5 pi}{6}, frac{7 pi}{6} ) Ams
Quick and Stepwise Solutions Just click and Send OVER 20 LAKH QUESTIONS ANSWERED Download App for Free