Question

( (i) )
( P vee=n R T )
( n=frac{p v}{R T} )
( =0.01864 mathrm{mol}_{2} mathrm{O}_{2} )
weight
of 2 produced = ( rightarrow 0+8 )
( =0.01864 mathrm{motes} times frac{32.0 mathrm{g}}{1 mathrm{mot}} )
( =0.596 mathrm{g} mathrm{O}_{2} )
ii) ( sigma cdot 01864 ) male ( frac{2 x}{3 operatorname{met} t cdot theta_{2}} )
( =0.01243 mathrm{mol}_{3} mathrm{RClD}_{3} )
solkuo, ( =frac{0.01243 times 122.559}{text { meter }} )
( - )
( =1.52 mathrm{g} times mathrm{a} 0.3 )
( =0.01243 ) moles ( mathrm{KC} )
( 0.9729 times 4 )

# 4. What volume of oxygen (NTP) will be required to react with no A sample of KC103 on decomposition yielded 448 mL of oxygen gas at NIE. Calculate: (a) Weight of oxygen produced (b) Weight of KClO3 originally taken, and (C) Weight of KCl produced. (K = 39, C1 = 35.5 and 0 = 16) 1 . coriac of recents so as to convert 11 of 1

Solution