Question

( 4000 x^{0} ) photon is wod to break the iodine movements, then the percentage of energy wruerted to the kinetic energy of iodine actors if bond dissociation energy of ( I_{2} ) molecules is 246.5kJ/mol
Solution

Energy of one photon ( =frac{12400}{4000}=3.1 mathrm{ev} )
Energy supplied by one mole photon in KJ/mole ( =3.1 times 1.6 times 10^{-19} times 6 times 10^{23} times 10^{-3}=297 mathrm{kJmol}^{-1} )
( % ) of energy converted to K. E.
( =frac{297-246.5}{297}=17 % )