Question

42. (1) Slant height ( =sqrt{12^{2}+16^{2}} )
[
=sqrt{400}=20 mathrm{m}
]
Canvas required ( = ) Curved surface area of conical tent
[
=pi r l=frac{22}{7} times 12 times 20=frac{5280}{7} mathrm{m}^{2}
]

# 42. A conical tent of nical tent of a diameter 24 m he base and its height 16 m. e canvas required to make it is (1) 5280 m2 (2) 5180 m2 (4) 3480 m² 1 7 (3) 4180 m2

Solution