Question

When they follow same trajectory,
their range and height must be same
range
( frac{u^{2} sin 2 theta}{g}=frac{v^{2} sin 2 phi}{g^{prime}} )
height
( frac{u^{2} sin ^{2} theta}{2 g}=frac{v^{2} sin ^{2} phi}{2 g^{prime}} )
On ssolving these two equations we
get
( theta=phi )
( frac{u^{2} sin 2 theta}{g}=frac{v^{2} sin 2 theta}{g^{prime}} )
( frac{g^{prime}}{g}=frac{v^{2}}{u^{2}}=frac{9}{25} )
( g^{prime}=frac{9}{25} times 9.8=3.5 m / s^{2} )

# 43. A projectile is fired from the surface of the earth with a velocity Of 5 m s-1 and angle with the horizontal. Another projectile fired from another planet with a velocity of 3 m s-lat the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in ms-2) is (given g = 9.8 ms -2) (a) 3.5 (b) 5.9 (d) 110.8. (c 16.3

Solution