Question

( f(x)=4^{x}+2^{x}+1 )
( =left(2^{x}right)^{2}+2^{x}+1 )
( f(x)=t^{2}+t+1 quadleft(t=2^{x}right) )
( f(x)=t^{2}+t+1 )
[
-4 cdot 1 cdot 1=-3<0
]

# 43. Range of f(x) = 4* + 2x + 1 is (a) (0,0) (b) (1.) (c) (2 ) (d) (3,)

Solution