Question

44. (4) Now, radius of conical tent, ( r=frac{12}{2}=6 mathrm{m} )
[
I=sqrt{(8)^{2}+(6)^{2}}=sqrt{64+36}=sqrt{100}
]
( 1=10 mathrm{m} )
Now, surface area of conical tent ( =pi r l=frac{22}{7} times 6 times 10 mathrm{m}^{2} )
( therefore ) The cost of canvas required for a conical tent ( =frac{22}{7} times 6 times 10 times 3.5=₹ 660 )

# 44. The cost of canvas required for a conical tent of height 8 m and diameter of base 12 m. At the rate of 3.50 per m’is (1) * 620 (2) 600 (3) 640 (4) *660

Solution