Question

44. (2) Here, ( A B ) is the height of Light house ( B C ) is the distance of ship from Light hour
Then By Trigonometric ratio
[
begin{aligned} tan 30^{circ} &=frac{A B}{B C} Rightarrow frac{1}{sqrt{3}}=frac{20}{B C} B C=& 20 sqrt{3} &left[tan 30^{circ}=frac{1}{sqrt{3}} text { Trigonometric ratio }right] end{aligned}
]

# 44. The height of a light house is 20 above sea level. The angle of depression (from the top of the lighthouse) of a ship in the sea is 30°. What is the distance of the ship from the foot of the light house? RRB NTPC (Phase I) 2016 (1) 16 m (2) 2013 m (3) 20 m (4) 30 m

Solution