Question

45. (3) We know that, ( C=Pleft(1+frac{r}{100}right)^{n} )
After one year
[
begin{aligned}
text { Principle } &=500left(1+frac{10}{100}right)^{1}+500
&=frac{500 times 11}{10}+500
&=1050
end{aligned}
]
So, maturity value at end of 2 end years
[
begin{array}{l}
=1050left(1+frac{10}{100}right)^{1}=1050 times frac{11}{10}
=₹ 1155
end{array}
]

# 45. A man deposit 500 at the beginning of each year for 2 yr at 10% per annum compound annually. Find the maturity value at the end of the 2nd year. RRB NTPC (Phase-1) 2016 (1) 1050 dis (2) *1150 (3) 1155 lein (4) * 1200

Solution