Question

45. (4) : Total number of boys ( =1100 )
and total number of girls ( =900 )
( therefore ) Total number of passed boys
[
begin{aligned}
&=50 % times text { of } 1100
=& frac{50 times 1100}{100}=550
end{aligned}
]
and total number of passed girls ( =40 % ) of 900
[
=frac{40 times 900}{100}=360
]
Thus, total number of passed students
[
=550+360=910
]
( therefore ) Total number of failed students
[
=1100+900-910=1090
]
Hence, required per cent of failed students
[
=frac{1090}{2000} times 100 %=54.5 %
]

# 45. In an examination, 1100 boys and 900 girls appeared. 50% of the boys and 40% of the girls passed the examination. The percentage of candidates who failed (1) 45% (2) 45.5% (3) 50% (4) 54.5%

Solution