45. The solution of linear differen...
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45. The solution of linear differential equation rsino, dr te cos0=p2 is do (a) sece (b) sin 0+C cos O () – sin +C cose sin 0-C cos

JEE/Engineering Exams
Maths
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( frac{r sin theta d theta-d r cos theta}{cos ^{2} theta r^{2}}=frac{d theta}{cos ^{2} theta} ) ( frac{r tan theta sec theta d theta-d r sec theta=sin ^{2} theta d theta}{r^{2} d(tan theta)} ) [ begin{aligned} intleft(frac{sec theta}{r}right)=& frac{sec theta}{r}=tan theta+c r &=frac{sec theta}{tan theta+c} end{aligned} ] ( =frac{sin theta+cos theta}{cos theta}=frac{1}{sin theta+operatorname{cccos} theta} )
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