Question

( x^{2}+y^{2}=9 )
(1)
( x^{2}+y^{2}-12 y+27=0 quad ) is
put is in lij
( Rightarrow 9-12 y+27=0 )
( y=3 )
( p+t y=3 ) in (1)
( x^{2}+9=9 )
( x=0 )
point of contact ( =[0,3] )
tangent equation ( x x+y y_{1}=9 )
( 0+3 y=9 )
( y=3 )

# 47. ♡ - The circles x2 + y2 = 9 and x2 + y2_12y + 27 = 0 touch each other then the equatiðn of the common tangent 15. a) x - 3y + 1 = 0 b) y = 3 c) x+y=2 d) X=4

Solution