Question

( f(f(x)) )
( x<-1 )
[
f(x)=|x|
]
( f(f(x)=2-|x| )
( cos 2 cdot operatorname{tur} x geq-1 leq x leq 1 )
( f(x)=|x| )
( f(f(x)=|f(x)|=|x| )
Care 3 ( f o x quad x>1 )
( f(x)=frac{2-x}{1} )
( operatorname{So,} fleft(f(x)=mid begin{array}{cc}x & <1 f(x)end{array}right] )
( =(2-x) )
Frhus ( quad ) Ams 1

# 48. If S(x)= (2x), then f(f(x) = 12-1*1,*<-1 , x,x<-1 112-x|,*<-1 1}x, -15x51 2) 2–1x|,-1x513) |x,-15xs1 [12–x,x>1 1 12- x,x>1. 12- x,x>1 4) Cannot say

Solution