Question

No. of moles = molarity X Volume ( L)
( mathrm{AgNO}_{3}=0.005 mathrm{mol} times 200 mathrm{mL} )
( =0.005 frac{operatorname{mol}}{x} times 0.27 )
( =0.001 mathrm{mol} )
11)
( n_{k C L}=0.01 ) mol ( x 300 mathrm{ml} )
( =operatorname{orfin}(2) )

# 49. 200 ml of 0.005 M AgNO, reacts with 300 ml of 0.01 M KCL. IfK of AgCl is 1.8% 10-16. Then maximum conc. of Ag in mixture is :- (1) 2 x 108 (2) 4.5 x 105 (3) 4.8 x 105 (4) 1.34 × 105

Solution