Question

( lim _{x rightarrow 3} frac{sqrt{n+1}-sin (n-3)-3}{(x-3) cos (x-3)} )
Appició ('hifital rule
[
begin{array}{c}
lim _{x rightarrow infty} frac{1}{2 sqrt{x+6}}-operatorname{lis}(x-3)
sin (x-3)-(1-3) sin (m+3)
frac{1}{2 cdot 3}-1
frac{1}{2}-5 / 6
end{array}
]

# 4x+6 - sin(x-3)-3 1-3 (x-3)cos(x-3) is equal to :

Solution