4x+6 - sin(x-3)-3 1-3 (x-3)cos(x-3)...
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4x+6 - sin(x-3)-3 1-3 (x-3)cos(x-3) is equal to :

JEE/Engineering Exams
Maths
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( lim _{x rightarrow 3} frac{sqrt{n+1}-sin (n-3)-3}{(x-3) cos (x-3)} ) Appició ('hifital rule [ begin{array}{c} lim _{x rightarrow infty} frac{1}{2 sqrt{x+6}}-operatorname{lis}(x-3) sin (x-3)-(1-3) sin (m+3) frac{1}{2 cdot 3}-1 frac{1}{2}-5 / 6 end{array} ]
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