5-30 = = 25 = 3b = a - b - C = 36 S...
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5-30 = = 25 = 3b = a - b - C = 36 Show that (b-c32006+(6+oʻsin = 2? = 62-2bc- Sol. LHS. = (-c) cos? --C) sin

JEE/Engineering Exams
Maths
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( (b-c)^{2} cos ^{2} A / 2+(b+c)^{2} sin ^{2} A / 2 ) ( Rightarrowleft[b^{2}+c^{2}-2 b cright] cos ^{2} A / 2+left[b^{2}+c^{2}+2 b cright] sin ^{2} A / 2 ) ( Rightarrowleft[b^{2}+c^{2}right] cos ^{2} A / 2+2 b cleft[sin ^{2} A / 2^{-cos ^{2} A / 2}right] ) ( =left[b^{2}+c^{2}right] cos ^{2} A_{2}+left[b^{2}+c^{2}right] sin ^{2} A_{2} ) ( =b^{2}+c^{2}-2 b c cos A Rightarrow a^{2} ) triangle law
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