Question

For series, let Resistance be ( R ) each, since same material thre, beth and dimensions are is tauce, will have same
[
begin{array}{l}
quad R_{e q}=2 R
text { And for parallel }
end{array}
]
[
begin{aligned}
R_{e q} &=frac{1}{frac{1}{R}+frac{1}{R}}
&=frac{R}{2}
end{aligned}
]
Heat produced = i ( ^{2} R )
(where " is worent)
matio is:
[
frac{i^{2}(2 R)}{i^{2}left(frac{R}{2}right)}=4: 1
]

# 5.4. Two conducting wires of the same material an equal lengths, and equal diameters are first connecta in series and then in parallel in an electric circuit. Th ratio of the heat produced in series and parallel combinations would be : | (a) 1:2 (6) 2:1 (c) 1:4 (d) 4:1

Solution