Question

( log _{4} log _{3} log _{2} 2^{9}+2 log _{16} 8 )
( log _{4} 20933^{2}+log _{16} 64 )
( log _{4} 2 )
( frac{1}{2} log _{2} 2+frac{10 g 16}{15}+frac{1}{2} log _{4} 4 )
( 1+frac{1}{2}+frac{1}{2}=2 )

# 5. (A) 0 (BT log,log, log,512 + 2log, 8 is equal to - (A) 2 (B)3 (C) 5 (D) 7 OTTON TT 6

Solution