Question

Ins ABC
[
B+C=140^{circ}
]
( - )
( D-frac{(11)}{Rightarrow} quad A=180^{circ}-140 )
[
begin{array}{r}
Rightarrow frac{sqrt{A}=40^{circ}}{.80^{circ}-left(185^{circ}+40^{circ}right)}
therefore quad 180^{circ}-155^{circ}
end{array}
]

# 5. I AABC, LA + LB =65° s and LB + L9F140° sf und the measure of each angle of the trangle.

Solution