5 If ey + xy = e, the ordered pair ...
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5 If ey + xy = e, the ordered pair atx=0 is equal to ਰੇ ਵਿਚ

JEE/Engineering Exams
Maths
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[ begin{array}{l}e^{y}+x y=e text { at reo, }left[e^{y}=e^{frac{2}{y}}=1right]end{array} ] Dilferentiate wort. ( x ) wehave, five ( quad e^{y} frac{d y}{d x}+left[y+x frac{d y}{d x}right]=0 ) your ( left(e^{y}+xright) frac{d y}{d x}=-y rightarrow a ) leadbacie fendback ( quad frac{d y}{2} ) at ( x=0 ) ( (9806) 09678)left(-8^{y}+0right) frac{d y}{d x}=-y ) ( lg operatorname{ain}_{1} e frac{d y}{a x}=-1 Rightarrowleft(frac{d y}{a u}=frac{-1}{e}right) ) diff ear" ( left(frac{e^{y} d y}{d x}+1right) frac{d y}{d x}+left(e^{y}+yright) frac{d^{2} y}{d x}=-frac{d y}{d x} ) ( a+x=0 quad(x-1)+1 quadleft[-frac{1}{e}right)+left(e cdot frac{2 b}{a x^{2}}right)=frac{1}{e} ) ( S O,left(-frac{1}{e}, frac{1}{e}right) sim | frac{T^{-h_{1}}}{partial u^{2}}=frac{1}{e^{2}} )
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