Question

( x^{2}+2 x-3 geq 0 )
( (x+3)(x-1) geqslant 0 )
( x in(-infty,-3] cup[1, infty)-0 )
( x^{2}-2 x-3 geq 0 )
( (x-3)(x+1) geq 0 )
( x in(-infty,-1] cup[3, infty)-(11) )
( operatorname{lom}(10 x(11) )
( x in(-infty,-3) cup(3, infty) )

# 5. If x²+2x-3 2 0 and x? - 2x-3 20 then

Solution