5. (x+3) (1-5) > 0 then xe (a) (3.5...
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5. (x+3) (1-5) > 0 then xe (a) (3.5) (b) (-.-3]+[5.--) (0) (-3,5) (d) (..-3) (5.c)

JEE/Engineering Exams
Maths
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( (1+9)(n-5)>0 ) ( x+3>0 ) ( x>-3 )( left{begin{array}{l}(x-6)>0 x+75end{array}right. ) ( frac{t}{-3}-frac{t}{6}+alpha ) ( x in(-infty,-3) cupleft(5, x^{prime}right) )
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