Question

( (1+9)(n-5)>0 )
( x+3>0 )
( x>-3 )( left{begin{array}{l}(x-6)>0 x+75end{array}right. )
( frac{t}{-3}-frac{t}{6}+alpha )
( x in(-infty,-3) cupleft(5, x^{prime}right) )

# 5. (x+3) (1-5) > 0 then xe (a) (3.5) (b) (-.-3]+[5.--) (0) (-3,5) (d) (..-3) (5.c)

Solution